By using Newton Raphson Method, x^4-x-10=0 which is nearest to 2, find real root correct to three decimal places? (R.G.P.V. 2022 NOV)

Solution: Let,                   F(x)= x^4-x-10 Here, f’(Xn)= 4x^3-1 According to the question, it will be given x0= 2.. X0+1= x0- (x0^(4)-x0-10)/(4×0^(3)-1) X1=x0-(x0^(4)-x0-10)/(4×0^3-1) Put the value … Read more

Find the real root of the Equcation: f(x) =x^3-4x-9=0 by using bisection method/ Bolzano method upto 3 decimal places ?

Solution: Let,                      F(x)=x^3-4x-9=0 Now,  Put x=0:- 0^(3)-4*0-9= -9 (-ve)  Put x=1:- 1^(3)-4*1-9= -13 (-ve) Put x=2:- 2^(3)-4*2-9= -9 (-ve) Put x=3:- 3^(3)-4*3-9= 6 (+v) … Read more

Find the real root of the Equcation: f(x) =x^3-2x-5=0 by using bisection method/ Bolzano method in Five stage ?

Solution: Let,                      F(x)=x^3-2x-5=0 Now,  Put x=0:- 0^(3)-2*0-5= -5 (-ve) Put x=1:- 1^(3)-2*1-5= -6 (-ve) Put x=2:- 2^(3)-2*2-5= -1 (-ve) Put x=3:- 3^(3)-2*3-5= 16 (+v) … Read more